Помагите пж оешить [latex] x^{2} -12x \geq 2x-12- x^{2} [/latex]

[latex] x^{2} -12x \geq 2x-12- x^{2} \\ x^2-12x-2x+12+x^2=0 \\ 2x^2-14x+12=0 \\ x^2-7x+6=0 \\ x^2-x-6x+6 = 0 \\ x(x-1)-6(x+1)=0 \\ (x-6)(x-1) = 0 \\ x-6 = 0 \\ x-1=0 \\ x_1=6 \\ x_2= 1[/latex]