Pomogite pojaluista s etimi uravneniyami

[latex] \frac{(26\frac{4}{5}-23\frac{3}{7}):\frac{6}{35}}{x}-29\frac{5}{6}= 9\frac{1}{3}\\\\ \frac{( \frac{134}{5}-\frac{164}{7}):\frac{6}{35} }{x} -\frac{179}{6}=\frac{28}{3}\\\\ \frac{ \frac{118}{35}\cdot \frac{35}{6} }{x} =\frac{28}{3}+\frac{179}{6}\\\\ \frac{118}{6x} = \frac{235}{6} \\\\\frac{118}{x}=235\\\\x= \frac{118}{235} [/latex]