Помогите, пожалуйста. Срочно 1)40√3 cosπ/6 cos5π/3 2)8√6 cosπ/4 cos5π/6 3)14√6 cosπ/6 cos3π/4 4)28/(sin(-25π/4)cos(23π/4)) 5)23/(sin(-23π/6)cos(23π/3)) 6)60/(sin(-32π/3)cos(35π/6)) 7)54/(sin(-28π/3)cos(23π/6)) 8)33√2cos(495°)

Решение: 1) 40√3·√3/2·(-√2/2)=20·√3·√3·(-√2/2)=10·3·(-√2)=-30√2 2) 8√6 ·√2/2 ·(-√3/2)=4√6·√2·(-√3/2)=2√6·√2·(-√3)=-2√6·2·3=-2√36=-2·6=-12 3) 14√6 ·√3/2· (-√2/2)=7√6·√3·(-√2/2)=-7√18·(√2/2) 4) 28/(sin(-25π/4)cos(23π/4))=28/(-sin(6π+π/4)cos(5π+3π/4))=28/(-√2/2)·(1+(-√2/2))=14/(-√2/)·(1-√2/2) 5)23/(sin(-23π/6)cos(23π/3))=23/(sin(-3π+5π/6)cos(7π+2π/3))=23/(-1/2)(1-1/2)=23/(-1/4)=-23/4 6)60/(sin(-32π/3)cos(35π/6))=60/(sin(-10π +2π/3)cos(5π+5π/6))=60/(-√3/2)(1+(-√3/2))=-30√3·(1-√3/2)=-30√3+15·3=-30√3+45 7)54/(sin(-28π/3)cos(23π/6))=54/(-sin(9π)cos(5π+3π/6))=54/(0·cos(5π+3π/6)=54/0 8)33√2cos(495°)=33√2cos(360°+135°)=33√2cos(2π+3π/4)=33√2·(1-√2/2)=33√2-33√2·(√2/2)=33√2-33·2/2=33√2-33