Помогите решить! 1)в,г 2)в,г

1) а)(а+3)²-(а-2)(а+2)=а²+6а+9-а²+4=6а+13=-3.5*6+13=-8 b)(x-3)²-(x-3)(x+3)=x²-6x+9-x²+9=-6x+18=0.1*6+18= 18,6 2) a)(5a-10)²-(3a-8)²+132a=25a²-100a+100-9a²+48a-64+132a=16a²+32a+48a+36=16a²+80a+36=16*36- 80*6+36=132 b)(3p-8)²+(4p+6)²+100p=9p²-48p+64+16p²+48p+36+100p=25p²+100p+100=(5p-10)²=(-20)²=400