Помогите решить!!!))) 4x^2=7x-3. 2x^2+5=-7x

1.)  [latex]4 x^{2} -7x+3=0[/latex] [latex] x_{1,2} = \frac{7+- \sqrt{49-48} }{8} [/latex] [latex] x_{1} = \frac{7+1 }{8} =1[/latex] [latex] x_{2} = \frac{7-1}{8}= \frac{6}{8} = \frac{3}{4} =0,75[/latex] 2.)  [latex]2 x^{2} +7x+5=0[/latex] [latex]x_{1,2} = \frac{-7+- \sqrt{49-40} }{4}[/latex] [latex]x_{1} = \frac{-7+3}{4}= -1[/latex] [latex]x_{2} = \frac{-7-3}{4}= - \frac{10}{4} =-2,5[/latex]

4x²=7x-3                D=b²-4ac 4x²-7x+3=0 a=4 b=-7 c=3 D=(-7)²-4×4×3=49-48=1  √D=1 x₁=7-1/2×4=6/8=3/4 x₂=7+1/2×4=8/8=1 2x²+5=-7x 2x²+7x+5=0 a=2 b=7 c=5 D=7²-4×2×5=49-40=9 √D=3 x₁=-7-3/2×2=-10/4=-5/2 x₂=-7+3/2×2=-4/4=-1