Помогите решить 80 баллов а)7*3^x+1-3^x+4=5^x+2-5^x+3 б)2^x-2^x+2+2^x-1=(3^x+1-3^x+2+3^x)*2/9

[latex]7*3^{x+1}-3^{x+4}=5^{x+2}-5^{x+3}[/latex] [latex]7*3*3^{x}-3^4*3^{x}=25*5^{x}-125*5^{x}[/latex] [latex]-60*3^{x}=-100*5^{x}[/latex] [latex]-60*3^{x}=-100*5^{x}[/latex] [latex]3*3^{x}=5*5^{x}[/latex] [latex]3^{x+1}=5^{x+1}[/latex] [latex]( \frac{3}{5}) ^{x+1}=1[/latex] [latex]( \frac{3}{5}) ^{x+1}= (\frac{3}{5} )^0[/latex] [latex]x+1=0[/latex] [latex]x=-1[/latex] ---------------------------------------------------------------------------- [latex]2^x-2^{x+2}+2^{x-1}=(3^{x+1}-3^{x+2}+3^x)* \frac{2}{9} [/latex] [latex]2^x-4*2^{x}+ \frac{1}{2}* 2^{x}=(3*3^{x}-9*3^{x}+3^x)* \frac{2}{9} |*2[/latex] [latex]2*2^x-8*2^{x}+ 2^{x}=(3*3^{x}-9*3^{x}+3^x)* \frac{4}{9}[/latex] [latex]-5*2^{x}=(-5*3^x)* \frac{4}{9}[/latex] [latex]2^{x}=3^x *(\frac{2}{3})^2[/latex] [latex] (\frac{2}{3})^x =(\frac{2}{3})^2[/latex] [latex]x=2[/latex]