Помогите решить, √х+1=х+5

[latex] \sqrt{x+1} = x - 5[/latex] [latex]x + 1 = (x-5)^2[/latex] [latex]x + 1 = x^2 - 10x + 25[/latex]  [latex]-x^2 + 11x - 24 = 0[/latex] [latex]-(x-8)(x-3) = 0[/latex] [latex](x-8)(x-3) = 0[/latex] ⇒ [latex] \left \{ {{x1 = 8} \atop {x2 = 3}} \right. [/latex] [latex]x = 8[/latex]