Помогите решить пример (12 13/30*2 1/10 -25 3/5):16/25 + 3 1/4=

[latex](12\frac{13}{30}*2\frac{1}{10}-25\frac{3}{5}):\frac{16}{25}+3\frac{1}{4}[/latex] 1.[latex]12\frac{13}{30}*2\frac{1}{10}=\frac{373}{30}*\frac{21}{10}=\frac{373*21}{30*10}=\frac{7833}{300}=\frac{2611}{100}=26\frac{11}{100}[/latex] 2.[latex]26\frac{11}{100}-25\frac{3}{5}=(26\frac{11}{100}-25\frac{3}{5})=1\frac{11}{100}-\frac{60}{100}=\frac{111}{100}-\frac{60}{100}=\frac{111-60}{100}=\frac{51}{100}[/latex] 3.[latex]\frac{51}{100}:\frac{16}{25}=\frac{51*25}{100*16}=\frac{51*1}{4*16}=\frac{51}{64}[/latex] 4.[latex]\frac{51}{64}+3\frac{1}{4}=\frac{51}{64}+\frac{13}{4}=\frac{51+(13*16)}{64}=\frac{51+208}{64}=\frac{259}{64}=4\frac{3}{64}[/latex]