Помогите решить уравнение: (х-4)²(х-3)=0 (х²-4)(х+1)=0 х(х²+4)(х+4)=0 (х-5)(х³+1)=0

( x - 4)^2(x- 3) = 0 x - 4 = 0 x = 4 x - 3 = 0 x = 3 (x^2 - 4)(x + 1) = 0 x^2 - 4 = 0 x^2 = 4 x = 2 x = - 2 x+ 1 = 0 x = - 1 x(x^2 + 4)(x + 4) = 0 x = 0 x^2 + 4 = 0 x^2 = - 4 - корней нет x + 4 = 0 x = - 4 ( x - 5)(x^3 + 1) = 0 x - 5 = 0 x = 5 x^3 + 1 = 0 x^3 = - 1 x = - 1