Ребят срочно надо, помогите 3^2x+1-4•3^x+1+9=0

[latex]3 ^{2x+1} -4*3 ^{x+1} +9=0, \\ 3*3 ^{2x} -4*3*3 ^{x} +9=0, \\ 3*3 ^{2x}-12*3 ^{x} +9=0, \\ 3 ^{x}=t, t\ \textgreater \ 0 \\ 3t ^{2} -12t+9=0, \\ D=(-12) ^{2} -4*3*9=144-108=36, \\ t_{1} = \frac{12- \sqrt{36} }{2*3}= \frac{6}{6} =1, t_{2} = \frac{12+ \sqrt{36} }{2*3} = \frac{18}{6} =3, \\ 3 ^{x} =1, x_{1}=0, \\ 3^{x}=3, x_{2}=1. \\ [/latex]