Решение уравнение 8х(1+2х)-(4х+3)(4х-3)=2х

8x + 16x^2 - (16x^2 - 9) = 2x 8x + 16x^2 - 16x^2 + 9 - 2x = 0  6x + 9 = 0  6x = - 9 x = - 9/6 = - 3/2 = - 1,5 

8x × (1 + 2x) — (4x + 3)(4x — 3) = 2x 8x + 16x² — 16x² + 9 = 2x 8x — 2x = —9 6x = —9; x = —[latex] \frac{9}{6} [/latex] = —1,5