Решить неравенство: [latex]x+3\ \textless \ (x+1)^{2} [/latex]

[latex]x+3\ \textless \ (x+1)^{2}\\x+3\ \textless \ x^2+2x+1\\x^2+x-2\ \textgreater \ 0\\x^2+x-2=0\\x_{1,2}=\frac{-1^+_-\sqrt{9}}{2}=\frac{-1^+_-3}{2}\\x_1=1\ ;x_2=-2\\(x-1)(x+2)\ \textgreater \ 0\\///(+)///(-2)...(-)...(1)///(+)///\ \textgreater \ x\\x\in(-\infty;-2)\cup(1;+\infty)\\OTBET:x\ \textless \ -2;x\ \textgreater \ 1[/latex]