Решить систему уравнений x+y=13 √x+√y=5

V x = a ; V y = b ; Х >= 0 ; y >= 0 a + b = 5 a = 5 - b ( 5 - b )^2 + b^2 = 13 25 - 10b + b^2 + b^2 = 13 2b^2 - 10b + 12 = 0 2( b^2 - 5b + 6 ) = 0 D = 25 - 24 = 1 b1 = ( 5 + 1 ) : 2 = 3 b2 = ( 5 - 1 ) : 2 = 2 a1 = 5 - 3 = 2 a2 = 5 - 2 = 3 V x = a V x = 2 X1 = 4 V x = 3 X2 = 9 V y = b V y = 3 y1 = 9 V y = 2 y2 = 4 Ответ ( 4 ; 9 ) ; ( 9 ; 4 )