Решить систему уравнений x^3-y^3=56 и x^2+xy+y^2=28

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1)x³-y³=56 x²+xy+y²=28 2)    |(x-y)(x²+xy+y²)=56     ÷ |x²+xy+y²=28 ______________________ (x-y)(x²+xy+y²)/x²+xy+y²=56/28 x-y=2 x=2+y 3) x=2+y (2+y)³-y³=56 (2+y-y)[(2+y)²+(2+y)y+y²)=56 4+4y+y²+2y+y²+y²=28 3y²+6y-24=0 y²+2y-12=0 k=1 D=1+24=25 y1=-6  y2=4 4)y=-6 x=2-6=-4 y=4 x=2-4=-2 ответ:(-4;-6);(-2;4)