Решить системы уравнений: 1) x-y=2 и 3^((x^2)+y)=1/9 2)x+2y=3 и 3^(x-y)=81

[latex]1)3^x*2^y=1/9[/latex] [latex]y-x=2[/latex] [latex]3^x*2^y^3^2=1[/latex] [latex]y=2+x[/latex] [latex]3^(x+2)*2^(x+2)=1[/latex]  [latex]((a^x*b^x=(ab)^x)[/latex] [latex]6^(x+2)=6^0[/latex] [latex]x+2=0[/latex] [latex]x=-2[/latex] [latex]y-(-2)=2 [/latex] [latex]y=0[/latex] Ответ:[latex]( -2,0)[/latex] [latex] 2) \left \{ {{x=3-2y} \atop {3^{x-y} =81}} \right.[/latex] [latex] \left \{ {{x=3-2y} \atop {3^{3-2y-y} =81}} \right.[/latex] [latex] \left \{ {{x=3-2y} \atop {3^{3-3y}=3^{4}}} \right.[/latex] [latex]3-3y=4[/latex] [latex]-3y=4-3 [/latex] [latex] y=- \frac{1}{3}[/latex] [latex]x=3-2y=3- \frac{2}{3}=\frac{7}{3}=2\frac{1}{3}[/latex] Ответ:[latex](2\frac{1}{3};-\frac{1}{3})[/latex]