Решить способом подстановки: {2х+3у=27 {х-у=11

2х+3у=27 х-у=11[latex] \left \{ {2x+3y=27} \atop {x-y=11}} \right. \left \{ {{2x+3y=27} \atop {x=11+y}} \right. [/latex] 22+2y+3y=27 5y=27-22 5y=5 y=5 x=11+y x=16