Решите 25 1\6 - (3 1\5+ 2 1\4) 5с решением

[latex]25 \frac{1}{6}-(3 \frac{1}{5}+2 \frac{1}{4})*5=25 \frac{1}{6}-( \frac{16}{5} + \frac{9}{4})*5=25 \frac{1}{6} -( \frac{16*4+9*5}{20} )*5= [/latex] [latex]=25 \frac{1}{6}- \frac{109}{20} *5=25 \frac{1}{6} - \frac{109}{4} = \frac{151}{6} - \frac{109}{4} = \frac{151*2-109*3}{12}= \frac{302-327}{12}= [/latex] [latex]= - \frac{25}{12} =-2 \frac{1}{12} [/latex]