Решите 5 любых, Срочно!!

1.2 f`(x)=(2+2x²-4x²)/(1+x²)²=(2-2x²)/(1+x²)² f`(-3)=(2-18)/(1+9)²=-16/100=-0,16 1.3 f`(x)=(x-1)`*√(x²+1)+(x-1)*(√(x²+1))`=1*√(x²+1)+(x-1)*2x/(2√(x²+1))= =√(x²+1)+x(x-1)/√(x²+1)=(x²+1+x²-x)/√(x²+1)=(2x²-x+1)/√(x²+1) f`(0)=(0-0+1)/√(0+1)=1/1=1 1.4 y`=1/3*3cos²x*(-sinx)+sinx=sinx*(-cos²x+1) y`(π/6)=sinπ/6*(-cos²π/6+1)=1/2*(-3/4+1)=1/2*1/4=1/8 1.5 f`(x)=4(x+1)/(x-1)*(x+1-x+1)/(x+1)²=4(x+1)/(x-1)*2/(x+1)²=8/[(x-1)(x+1)]=8/(x²-1) f`(-3)=8/(9-1)=8/8=1 1.6 f`(x)=5/(2√e^5x) f`(0)=5/(2√e)

1.1.f(x)=2·x³/²-3·x²/³+6·x¹/³  f'(x)=2·(2/3)·x³/²⁻¹-(3·2/3)x²/³⁻¹+6·`1/3·x¹/³⁻¹=(4/3)·x¹/²-2·x⁻¹/³+2·x⁻²/³= =4√x/3-2/∛x+2/∛x² f'(1)=4/3-2+2=4/3. 1.2.f(x)=2x/(1+x²).     f'(x)=2(1+x²)-2x·2x)/(1+x²)²=2+2x²-4x²)/( 1+x²)²=(2-2x²)/(1+x²)²     f'(-3)=(2-2·(-3)²)/(1(-3)²)²=(2-18)/10²=-16/100=-0.16 1.3.f(x)=(x-1)·√(x²+1)       f'(x)=√(x²+1)+(x-1)·1/2·√(x²+1)·2x=√(x²+1)+x(x-1)/·(x²+1)= =√(x²+1)+(1+x²-x)/ √(x²+1)  f'(0)=(√(0+1)+1+0-0)/√1)=1+1=2 1.4.f(x)=cos³x/3-cosx   f'(x)=3cos²x·(-sinx)/3+sinx=sinx(1-cos²x)=sinx·sin²x=sin³x   f'(π/6)=(1/2)³=1/8=0.125 1.5.f(x)=4ln(x-1)/x+1) f'(x)=4/(x-1)/(x+1)·((x+1)-(x-1))/(x+1)²)=(4(x+1)/(x-1))·2/(x+1)²=8/(x²-1) f'(-3)=8/((-3)²-1)=8/8=1 1.6.f(x)=√e⁵ˣ      f'(x)=1/2√e⁵ˣ ·e⁵ˣ·5=5√e⁵ˣ/3     f'(0)=5·e⁰/2=5/2=2.5 2.a(t)=v'(t)   a(t)=4t-3   a(3)=4·3-3=9(м/с²)   4t-3=0,4t=3,t=3/4=0,75c