Решите, пожалуйста: 9-√x-1=1/27

[latex]9-\sqrt{x-1}=\frac{1}{27}\; ,\; \; \; ODZ;\; x \geq 1\\\\\sqrt{x-1}=9-\frac{1}{27}\\\\\sqrt{x-1}= \frac{242}{27} \\\\x-1=( \frac{242}{27} )^2\\\\x= \frac{58564}{729} +1\\\\x= \frac{59293}{729} [/latex]