Решите пожалуйста номера: 1,2,4,6

1. 4a²/-8a^3 = -1/2a = -0.5a 2. 30c^3a²/48a^3c² =5c/8a 4. (a²+ab)/(a²-b²) =a(a+b) /(a-b)(a+b) =a/(a-b) 6. a/(a+b) - b/(a-b) =(a(a-b) -b(a+b)) /(a-b)(a+b) =(a²-ab -ab-b²) /(a² -b²) =(a² -2ab -b²) /(a²-b²)

[latex]1)\; \; \frac{48a^2}{-8a^3} =-\frac{6}{a}\\\\2)\; \; \frac{30c^3a^2}{48a^3c^2} = \frac{5c}{8a} \\\\4)\; \; \frac{a^2+ab}{a^2-b^2} = \frac{a(a+b)}{(a-b)(a+b)} = \frac{a}{a-b} \\\\6)\; \; \frac{a}{a+b} - \frac{b}{a-b} = \frac{a(a-b)-b(a+b)}{(a-b)(a+b)} = \frac{a^2-2ab-b^2}{(a-b)(a+b)} = \frac{(a^2-2ab+b^2)-2b^2}{(a^2-b^2} =\\\\= \frac{(a-b)^2-2b^2}{a^2-b^2} = \frac{(a-b-\sqrt2b)(a-b+\sqrt2b)}{a^2-b^2} = \frac{(a-(1+\sqrt2)b)\cdot (a-(1-\sqrt2)b)}{a^2-b^2} [/latex]