Решите пожалуйста -x - 3x + 10 =0 100 - x^2 =0 -2x^2 =0 13 - x^2 =0 x^2 - 12x + 33 =0 -x^2 + x + 12 = 0 x^2 - 12x + 36 = 0 x^2 + 4x + 20 = 0

- 4x = - 10 4x = 10 x = 2,5 - x^2 = - 100 x^2 = 100 x = 10 x = - 10 - 2x^2 = 0 x^2 = 0 x =0 - x^2 = - 13 x^2 = 13 x = √13 x = - √13 x^2 - 12x + 33 = 0 D = b^2 - 4ac = 144 - 132 = 12 x1,2 = ( 12+/-√12) / 2 x^2 - x - 12 =0 D = b^2 - 4ac = 1 + 48 = 49 = 7^2 x1 = ( 1 + 7) / 2 = 4 x2 = ( 1 - 7) / 2 = - 3 x^2 - 12x + 36 = 0 D = b^2 - 4ac = 144 - 144 = 0 - имеет один корень x = - b/2a x = 12/2 = 6 x = 6 x^2 + 4x + 20 = 0 D = b^2 - 4ac = 16 - 80 = - 64 - дискиминант отрицательный,значит,корней нет.