Решите пример срочного

[latex] \frac{b-c}{b} - \frac{c^2}{b^2-bc} + \frac{2b}{b-c} = \frac{b-c}{b} -\frac{c^2}{b(b-c)} + \frac{2b}{b-c} = \frac{(b-c)(b-c)-c^2+2b^2}{b(b-c)} = [/latex][latex] \frac{b^2-2bc+c^2-c^2+2b^2}{b(b-c)} = \frac{3b^2-2bc}{b(b-c)} = [/latex][latex] \frac{b(3b-2c)}{b(b-c)} = \frac{3b-2c}{b-c} [/latex]