Решите пж номер 39.13(а)

A(2,3),B(-1,4) tg a = k = (y2-y1)/(x2-x1)=(4-3)/(-1-2)=1/(-3)=-1/3 y-y1=k(x-x1) y-3=-1/3(x-2) /.3 3y-9=-(x-2) 3y-9=-x+2 x+3y-11=0