Решите систему (4x+1)^2=12y (x+4)^2=3y

16x²+8x+1=12y x²+8x+16=3y y=(x²+8x+16)/3 16x²+8x+1=12*(x²+8x+16)/3 16x²+8x+1=(12x²+96x+192)/3 3(16x²+8x+1)=12x²+96x+192 48x²+24x+3=12x²+96x+192 48x²+24x+3-12x²-96x-192=0 36x²-72x-189=0 D=5184+27216=32400=180² x₁=(72+180)/72=3,5 x₂=(72-180)/72=-1,5 y₁=(3,5²+8*3,5+16)/3=(12,25+28+16)/3=56,25/3=18,75 y₂=(1,5²+8*1,5+16)/3=(2,25+12+16)/3=30,25/3=10,1