Решите систеу уравнений {x^2+2xy+y^2=1 {x^2-xy-4y^2=2

{x^2+2xy+y^2=1 {x^2-xy-4y^2=2 *************** {x^2+2xy+y^2=1 {x^2-xy-4y^2=2x^2+4xy+2y^2 *************** {x^2+2xy+y^2=1 {x^2+5xy+6y^2=0 *************** {(x+y)^2=1 {(x+2y)(x+3y)=0 *************** x=-2y (y-2y)^2=1 y=(+/-)1 x=(-/+)2 или x=-3y (y-3y)^2=1 y=(+/-)1/2 x=(-/+)3/2 ответ (-2;1);(2;-1);(-3/2;1/2);(3/2;-1/2)