Решите уравнение 144x^2-0,25=0 и 169y^2-0,36=0 ; (3+x)^2+(5-2x)(5+2x).

[latex] 144 x^{2} -0,25=0 \\ x^{2} =\frac{0,25}{144} \\ \\ x_{1} = \frac{0,5}{12} = \frac{1}{24} \\ x_{2} = -\frac{1}{24} \\ \\ y^{2} = \frac{0.36}{169} \\ \\ y_{1} = \frac{0.6}{13} = \frac{2}{65} \\ y_{2} = -\frac{2}{65} [/latex]