Решите уравнение: 2x^2+3x-2=0

[latex]a=2 b=3 c=-2[/latex] [latex] 2x^{2} +3x-2=0[/latex] [latex]D=b^{2}-4ac[/latex] [latex] x_{1} = \frac{-b+ \sqrt{D} }{2a} x_{2} = \frac{-b- \sqrt{D} }{2a} [/latex] [latex]D= 3^{2} -4*2*(-2)=9+16=25= 5^{2} [/latex] [latex] x_{1} = \frac{-3+ \sqrt{ 5^{2} } }{2*2} = \frac{2}{4} = \frac{1}{2} [/latex] [latex] x_{2} = \frac{-3- \sqrt{ 5^{2} } }{2*2} = \frac{-8}{4} =-2[/latex] Ответ: [latex] x_{1} = \frac{1}{2} x_{2} =-2[/latex]