Решите уравнение : (4х+1)^2=5y (x+4)^2=5y

5Y = 5Y  ( 4X + 1)^2 = ( X + 4)^2  ------------------------- 16X^2 + 8X + 1 = X^2 + 8X + 16  16X^2 - X^2 + 8X - 8X = 16 - 1  15X^2 = 15  X^2 = 1 X1 = 1 X2 = - 1  -------------- 5Y = X^2 + 8X + 16  5Y = 1 + 8 + 16 = 25  Y1 = 5  ---------- 5Y = 1 - 8 + 16 = 9  Y2= 9/5 = 1,8  ----------- Ответ ( 1 ; 5 ) ; ( - 1 ; 1,8 )