Решите уравнение 9х^2-4х-2=0

9x^2-4х-2=0 Д=16+72=88=[latex] \sqrt{4*22} =2 \sqrt{22} [/latex] х1=(4-[latex](2 \sqrt{22} )/18[/latex]=(2-[latex] \sqrt{22} )/9[/latex] x2=(4+[latex](2 \sqrt{22} )/18[/latex]=(2+[latex] \sqrt{22} )/9[/latex]