Решите уравнения с фотографии

1)[latex] \frac{(x-6)(x-6)-(x-12)(x-12)}{(X-12)(x-6)} = \frac{ x^{2} -6x-6x+36-( x^{2} -12x-12x+144)}{ x^{2} -6x-12x+72} = [/latex] [latex]= \frac{ x^{2} -12x+36- x^{2} +24x-144}{ x^{2} -18x+72} = \frac{12x-108}{ x^{2} -18x+72} [/latex] [latex]\frac{12x-108}{ x^{2} -18x+72} = \frac{5}{6} [/latex] 6(12х-108)=5(х²-18х+72) 72х-648=5х²-90х+360 5х²-162х+1008=0 D=b²-4ac=(-162)²-4·5·1008=26244-20160=6084 [latex] x_{1} = \frac{162- \sqrt{6084}}{2*5} = \frac{162-78}{10} = \frac{84}{10} =8,4[/latex] [latex]x_{2} = \frac{162+ \sqrt{6084}}{2*5} = \frac{162+78}{10} = \frac{240}{10} =24[/latex]

А сколько х равен и наверно решу