Решите уравнения. Спасибо. _________________________ 24х-3-(6+0,4х)=1 _________________________ 2х+(5-4х)=11

24x-3-(6+0,4x)=1 24x-3-6-0,4x=1 24x-0,4x=1+3+6 23,6x=10 [latex]x= \frac{10}{23,6} = \frac{10}{1} :23 \frac{6}{10} = \frac{10}{1} : \frac{236}{10} = \frac{10}{1} * \frac{10}{236} = \frac{100}{236} = \frac{50}{118} = \frac{25}{59}[/latex] [latex]x= \frac{23}{59} [/latex] 2x+(5-4x)=11 2x+5-4x=11 2x-4x=11-5 -2x=6 [latex]x= \frac{6}{-2} [/latex] [latex]x=-3[/latex]