Ответ(ы) на вопрос:
Гостьsin(x/2- π/6)+1=0 1 = sin(π/2) sin(x/2 - π/6) + sin(π/2) = 0 sin(x/2 - π/6) = -sin(π/2) sin(x/2 - π/6) = sin(-π/2) x/2 - π/6 = (3x - π)/6 (3x - π)/6 = -π/2 3x - π + 3π = 0 3x +2π = 0 3x = -2π x = -2π/3 Ответ: -2π/3
Гостьsin(x/2- π/6)+1=0 sin(x/2- π/6)= -1 x/2- π/6 = -π/2 + 2πn x/2 = π/6-π/2 + 2πn x/2 = -2π/6 + 2πn x = -2π/3 + 4πn
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