Система 2y+x^2=4 x-y=2

x - y = 2 => y = x-2 2y + x^2 = 4 => 2x - 4 + x^2 = 4 x^2 +2x - 8 = 0 x = -4 => y = -4-2 = -6 x = 2 => y = 2-2 = 0 ответ: (-4;-6), (2,0)

надеюсь поможет))))))