СРОЧНО!!!Вычислите: [latex](3 log_{7}2- log_{7}24) : ( log_{7}3 + log_{7}9 ) [/latex]

[latex](3log_72-log_7{24}):(log_73+log_79)=\\\\=(3log_72-log_7(8\cdot 3)):(log_73+log_73^2)= \\\\=(3log_72-(log_72^3+log_73)):(log_73+2log_73)=\\\\=(3log_72-3log_72-log_73):(3log_73)= \frac{-log_73}{3log_73} =-\frac{1}{3}[/latex]

(log₇ 2³ - log₇ 24) : (log₇ (3*9))=log₇ (8/24) : log₇ 27= =log₇ (1/3) : log₇ 3³ = log₇ 3⁻¹ : 3log₇ 3= -log₇ 3 : 3log₇ 3= -1/3