Упростить выражение[latex] \frac{1}{ x^{2} } + \frac{x-2}{x} [/latex][latex] \frac{2mn}{ m^{2} + n^{2} } + \frac{2m}{ m^{2} - n^{2} } - \frac{1}{m-n} [/latex]
Упростить выражение
[latex] \frac{1}{ x^{2} } + \frac{x-2}{x} [/latex]
[latex] \frac{2mn}{ m^{2} + n^{2} } + \frac{2m}{ m^{2} - n^{2} } - \frac{1}{m-n} [/latex]
Ответ(ы) на вопрос:
[latex] \frac{1}{ x^{2} } + \frac{x-2}{x} =\frac{1+x(x-2)}{ x^{2} }=\frac{1+x^{2} -2x}{ x^{2} }=\frac{(x-1)^2}{ x^{2} }[/latex]
[latex] \frac{2mn}{ m^{2} + n^{2} } + \frac{2m}{ m^{2} - n^{2} } - \frac{1}{m-n} =\frac{2mn}{ m^{2} + n^{2} } + \frac{2m}{ (m - n)(m+n) } - \frac{1}{m-n}[/latex] = [latex]\frac{2mn}{ m^{2} + n^{2} } + \frac{2m-(m+n)}{ (m - n)(m+n) }=\frac{2mn}{ m^{2} + n^{2} } + \frac{2m-m-n}{ (m - n)(m+n) }[/latex] = [latex]\frac{2mn}{ m^{2} + n^{2} } + \frac{m-n}{ (m - n)(m+n) }=\frac{2mn}{ m^{2} + n^{2} } + \frac{1}{ m+n }[/latex] = [latex]\frac{2mn(m+n)+m^2+n^2}{(m^{2} + n^{2})(m+n)}=\frac{2m^2n+2mn^2+m^2+n^2}{(m^{2} + n^{2})(m+n)}[/latex] = [latex]\frac{2m^2n+2mn^2+m^2+n^2+m^2n-m^2n+mn^2-mn^2}{(m^{2} + n^{2})(m+n)}[/latex] = [latex]\frac{(3m^2n+3mn^2+m^2+n^2)-m^2n-mn^2}{(m^{2} + n^{2})(m+n)} = \frac{(m+n)^3-mn(m+n)}{(m^{2} + n^{2})(m+n)}[/latex] = [latex]\frac{(m+n)((m+n)^2-mn)}{(m^{2} + n^{2})(m+n)} = \frac{(m+n)^2-mn}{m^{2} + n^{2}}[/latex] = [latex] \frac{m^2+2mn+n^2-mn}{m^{2} + n^{2}} = \frac{m^2+mn+n^2}{m^{2} + n^{2}}[/latex]
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