Упростите выражение: ([latex]- \frac{7}{x-3} +x+3[/latex]) [latex] \frac{x-3}{ x^{2} +8x+16}[/latex]

[latex].........= \frac{-7+x(x-3)+3(x-3)}{x-3}* \frac{x-3}{ x^{2} +8x+16}=\frac{-7+ x^{2} -3x+3x-9}{ x^{2} +8x+16} = \frac{ x^{2}-16 }{ (x+4)^{2} } =[latex] \frac{(x-4)(x+4)}{(x+4)(x+4)}= \frac{x-4}{x+4} [/latex]