Вычислите sin t и cos t,если:a)t=пи/6б)t=пи/2в)е=5пи/4г)t=-пи/3 

Решение: [latex]\sin \frac{\pi}{6}=\frac{1}{2}[/latex] [latex]\cos \frac{\pi}{6}=\frac{\sqrt 3}{2}[/latex] [latex]\sin \frac{\pi}{2}=1[/latex] [latex]\cos \frac{\pi}{2}=0[/latex] [latex]\sin \frac{5\pi}{4}=-\frac{\sqrt 2}{2}[/latex] [latex]\cos \frac{5\pi}{4}=-\frac{\sqrt 2}{2}[/latex] [latex]\sin \left (-\frac{\pi}{3})\right=-\sin \frac{\pi}{3}=-\frac{\sqrt 3}{2}[/latex] [latex]\cos (\left -\frac{\pi}{3})\right=\cos \frac{\pi}{3}=\frac{1}{2}[/latex]