√x2+4x+4 - √x2-6x+9 = 6

[latex] \sqrt{x^2+4x+2} - \sqrt{x^2-6x+9} =6 \\ \sqrt{(x+2)^2} - \sqrt{(x-3)^2} =6 \\ |x+2|-|x-3|=6[/latex] __-__-__[-2]__+__-__[3]__+__+___> [latex]\left[\begin{array}{ccc} \left \{ {{x \leq -2} \atop {-x-2+x-3=6}} \right. \\ \left \{ {{-2 \leq x \leq 3} \atop {x+2+x-3=6}} \right.\\ \left \{ {{x \geq 3} \atop {x+2-x+3=6}} \right. \end{array}\right\,\,\,\,\,\,\,\,\,\,\,\,\,\, \left[\begin{array}{ccc} \left \{ {{x \leq -2} \atop {-5=6}} \right. \\ \left \{ {{-2 \leq x \leq 3} \atop {x=3.5}} \right. \\ \left \{ {{x \geq 3} \atop {5=6}} \right. \end{array}\right \,\,\,\,\,\, \left[\begin{array}{ccc}\O\\\O\\\O\end{array}\right[/latex] Ответ: нет решений.