X^2+ix+1-3i=0 Помогите пожалуйста Срочно

[latex]\displaystyle x^2+\text{i}x+(1-3\text{i})=0\\\\\sqrt{D}= \sqrt{\text{i}^2-4(1-3\text{i})} = \sqrt{12\text{i}-5}= \sqrt{12\text{i}+4-9} = \\\\\sqrt{2^2+2\cdot 2\cdot 3\text{i}+(3\text{i})^2} = \sqrt{(2+3\text{i})^2} \\\\x_{1,2}= \frac{-\text{i}\pm(2+3\text{i})}{2}=(1+\text{i})\,,\,(-1-2\text{i}) [/latex]