Я повееешууусь.......... решите плииииз Sin^4x/4-cos^4x/4=1/2

5* 2tg (a/2) / (1+ tg^2 (a/2)) + (1-tg^2 (a/2)/ (1+tg^2 (a/2) ) = 5 10tg (a/2) + 1- tg^2 (a/2) = 5 +5tg^2 (a/2) 6tg^2 (a/2)-10tg(a/2)-4=0 tg(a/2) = x 6x^2 - 10x-4=0 3x^2 - 5x - 2=0 d=25+4*3*2=49 x1=2 x2=-1/3 tg (a/2)=2 a/2= arctg2+Pi*R a1=2arctg2+2Pi*R tg(a/2)=-1/3 a2=2arctg(-1/3)+2Pi*R 2) sin^4 x + cos^4 x = sin2x - 1/2 (cos 4x - 4cos2x +3)/8 + (cos 4x + 4cos2x +3)/8=sin2x - 1/2 2cos4x +6=(sin2x - 1/2)*8 2(1-2sin^2 2x) + 6 = 8sin2x - 4 sin^2 2x + 2sin2x - 3=0 a^2 + 2a -3 =0 D=4+4*3=16 a1=1 a2=-3 (no) sin2x=1 2x= Pi+2Pi*R