ЗАДАНИЕ №4 - сократить дробь, ОЧЕНЬ НАДО под А,Б

[latex]a)\ \frac{ \sqrt{5} +1}{ \sqrt{10}+ \sqrt{2} } = \frac{ \sqrt{5} +1}{ \sqrt{5}* \sqrt{2} + \sqrt{2} } = \frac{ \sqrt{5} +1}{ \sqrt{2} (\sqrt{5}+ 1) } = \frac{1}{ \sqrt{2} } = \frac{ \sqrt{2} }{\sqrt{2}*\sqrt{2}} = \frac{\sqrt{2}}{2} \\ \\ b) \frac{x^2-2}{ \sqrt{2}x+2 } = \frac{(x-\sqrt{2})(x+\sqrt{2})}{\sqrt{2}(x+\sqrt{2})} = \frac{x-\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}(x-\sqrt{2})}{\sqrt{2}*\sqrt{2}} = \frac{\sqrt{2}x-2}{2} [/latex]