№1 а) [latex] \frac{a^{2} b}{12c} * \frac{4c}{ab^{2} } [/latex] б) [latex]- \frac{2x}{3y} * \frac{y}{6x} [/latex] в) [latex] \frac{a^{2} -b^{2} }{a+3b} : \frac{ab+b^{2} }{2a+6b} [/latex] г) [latex] \frac{c ^{2} +4c+4}{2c-6} * ...
№1
а) [latex] \frac{a^{2} b}{12c} * \frac{4c}{ab^{2} }
[/latex]
б) [latex]- \frac{2x}{3y} * \frac{y}{6x} [/latex]
в) [latex] \frac{a^{2} -b^{2} }{a+3b} : \frac{ab+b^{2} }{2a+6b} [/latex]
г) [latex] \frac{c ^{2} +4c+4}{2c-6} * \frac{c^{2}-9 }{5c+10} [/latex]
№2
a) [latex] \frac{a}{a-b} - \frac{a-b}{a+b} [/latex]
б) [latex] \frac{a^{2} }{a^{2}-1 } - \frac{a}{a+1} [/latex]
в) [latex] \frac{a^{2} +y^{2} }{ay-y^{2} } - \frac{20}{a-y} [/latex]
г) [latex] \frac{a}{3a+3b} : \frac{a^{2} }{a^{2}-b^{2} } [/latex]
д) [latex](a+1+ \frac{1}{a-1} : \frac{a^{2} }{1-2a+a^{2} } [/latex]
Гость
Ответ(ы) на вопрос:
Гость№1
а
a/3b
б
-1/9
в
(a-b)(a+b)/(a+3b)*2(a+3b)/[b(a+b)]=2(a-b)/b
г
(c+2)²/[2(c-3)]*(c-3)(c+3)/[5(c+2)]=(c+2)(c+3)/10
№2
а
a/(a-b)-(a-b)/(a+b)=(a²+ab-a²+2ab-b²)/(a²-b²)=(3ab-b²)/(a²-b²)
б
a²/[(a-1)(a=1)]-a/(a-1)=(a²-a²+a)/(a²-1)=a/(a²-1)
в
(a²+y²)/[y(a-y)-20/(a-y)=(a²+y²-20y)/(ay-y²)
г
a/[3(a+b)]*(a-b)(a+b)/a²=(a-b)/3a
д
1)a+1+1/(a-1)=(a²-1+1)/(a-1)=a²/(a-1)
2)a²/(a-1)*(a-1)²/a²=a-1
Не нашли ответ?
Похожие вопросы