1. limx^2-9:x-3 x больше 3 2. lim x-3: корень х+1 и -2 х больше 3 3. lim x^2=x-6:x-2 x больше 2 помогитее

[latex] \lim_{x \to \3} \frac{ x^{2} -9}{x-3} = \frac{ 3^{2}-9 }{3-3} =[ \frac{0}{0} ][/latex] [latex] \lim_{x \to 3} \frac{ x^{2} -9}{x-3} = \lim_{x \to 3} \frac{(x-3)*(x+3)}{x-3} = \lim_{x \to 3} (x+3)=3+3=6[/latex] [latex] \lim_{x \to 3} \frac{x-3}{ \sqrt{x+1}-2 } =[ \frac{0}{0}] [/latex] [latex] \lim_{x \to 3} \frac{(x-3)*( \sqrt{x+1}-2)}{( \sqrt{x+1}-2 )*( \sqrt{x+1}+2 )} = \lim_{x \to 3} \frac{(x-3)*( \sqrt{x+1}-2 )}{( \sqrt{x+1} ) ^{2}-2^{2} } =[/latex] [latex]= \lim_{x \to 3} \frac{(x-3)*( \sqrt{x+1}+2) }{x-3} = \lim_{x \to 3} ( \sqrt{x+1} +2)= \sqrt{3+1}+2 =4[/latex]