1) log12 3 + log12 42) log7 98 - log7 23) log2 5 - log2 35 + log2 564) log1/3 5 - log1/3 5 + log1/3 9помогите пожалуйста как сможете1) lg4 + lg2502) log2 6 - log2 6/323) (log12 4 + log12 36)^24) lg13 - lg1305) (log2 13 - log2 5...
1) log12 3 + log12 4
2) log7 98 - log7 2
3) log2 5 - log2 35 + log2 56
4) log1/3 5 - log1/3 5 + log1/3 9
помогите пожалуйста как сможете
1) lg4 + lg250
2) log2 6 - log2 6/32
3) (log12 4 + log12 36)^2
4) lg13 - lg130
5) (log2 13 - log2 52)^5
6) (log0,3 9 - 2log0,3 10)^4
Решите уравнение
1) log3 x = -1
2) log2 x = -5
3) log3 x = 2
4) log4 x = 3
5) log4 x = -3
6) log7 x = 0
7) log1/7 x = 1
8) log1/2 x = -3
Вычислите
1) log2 log2 log3 81
2) log2 log3 log1/3 1/27
3) log√3 log5 125
4) log4 log3 81
как сможете помогите пожалуйста срочно заранее спасибо
Гость
Ответ(ы) на вопрос:
Гость1) log₁₂3 + log₁₂4 = log₁₂(3*4) = log₁₂12 = 1
2) log₇98 - log₇2 = log₇(98/2) = log₇49 = 2
3) log₂5-log₂35 + log₂56 = log₂(5/35) + log₂56 = log₂([latex] \frac{5*56}{35})= [/latex]log₂8 = 3
4) log₁/₃5 - log₁/₃5 + log₁/₃ 9 = log₁/₃9 = -2
1) lg4 + lg250= lg(4*250) = lg1000 = 3
2) log₂6 - log₂[latex] \frac{6}{32} [/latex] = log₂([latex] \frac{6*32}{6}) [/latex] = log₂32 = 5
3) (log₁₂4 + log₁₂36)² = (log₁₂144)² = 2² = 4
4) lg13 - lg 130 = lg[latex] \frac{13}{130} [/latex] = lg[latex] \frac{1}{10} [/latex] = -1
5) (log₂13-log₂52)⁵ = (log₂[latex] \frac{13}{52} [/latex])⁵ = (log₂[latex] \frac{1}{4} [/latex])⁵ = (-2)⁵ = -32
6) (log₀.₃9 - 2log₀.₃10)⁴ = (log₀.₃9 - log₀.₃100)⁴ = (log₀.₃[latex] \frac{9}{100} [/latex])⁴ = (log₀.₃0.09)⁴ = 2⁴ = 16
1) log₃x = -1
x = 3⁻¹ = 1/3
2) log₂x = -5
x = 2⁻⁵ = 1/32
3) log₃x = 2
x = 3² = 9
4) log₄x = 3
x = 4³ = 64
5) log₄x = -3
x = 4⁻³ = 1/64
6) log₇x = 0
x = 7° = 1
7) log₁/₇x = 1
x = 1/7
8) log₁/₂x = -3
x = (1/2)⁻³ = 8
1) log₂log₂log₃81 = log₂log₂4 = log₂2 = 1
2) log₂log₃log₁/₃(1/27) = log₂log₃3 = log₂1 = 0
3) [latex] log_{ \sqrt{3} } [/latex]log₅125 = [latex] log_{ \sqrt{3} } [/latex]3 = 2
4) log₄log₃81 = log₄4 = 1
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