100c^2+1-20c решите пожалуйста

[latex]100c^{2} +1-20c \\ 100c^{2} -20c+1 \\ 100c^{2} -20c+1 =0 \\ D=(-20)^{2} -4*100*1=400-400=0 \\ c _{0} = \frac{20}{200} =0.1[/latex] [latex]100c^{2} +1-20c=(10c-1)^{2} [/latex]