(11^x) + 2 - (11^x-1) =143

[latex]11^x-11^{x-1}=143-2 \\ 11^x-11^{x-1}=141 \\ 11^{x-1}(11-1)=141 \\ 11^{x-1}*10=141 \\ 11^{x-1}= \frac{141}{10} \\ \\ x-1=log_{11} \frac{141}{10} \\ \\ x=log_{11} \frac{141}{10} +log_{11}11 \\ \\ x=log_{11}( \frac{141}{10}*11 ) \\ \\ x=log_{11} \frac{1551}{10} [/latex]