(1/3)^-4 * 3^-2 + 1/12 * 3^2

[latex]( \frac{1}{3} )^{-4}*3^{-2}+ \frac{1}{12} *3^2=3^4*3^{-2}+ \frac{1}{12} *3^2=(3^2*3^{-2}+ \frac{1}{12} )*3^2=[/latex] [latex]=(3^0+ \frac{1}{12} )*9=(1+ \frac{11}{12} )*9= \frac{12+1}{12} *9= \frac{13}{12}*9= \frac{13}{14} *3= \frac{39}{4} =[/latex] [latex]=9 \frac{3}{4} =9,75[/latex]