1/5^х-1 - 1/5^х+1=4,8 Как такое решить? Можно с объяснениями

[latex]( \frac{1}{5})^{x-1} -( \frac{1}{5})^{x+1} =4,8\\\\ (\frac{1}{5})^{x}\cdot ( \frac{1}{5})^{-1}-( \frac{1}{5} )^{x}\cdot \frac{1}{5}=\frac{48}{10} \\\\ (\frac{1}{5})^{x} \cdot 5-( \frac{1}{5})^{x}\cdot \frac{1}{5} = \frac{24}{5} \\\\( \frac{1}{5})^{x}\cdot (5- \frac{1}{5})=\frac{24}{5} \\\\(\frac{1}{5})^{x}\cdot \frac{24}{5}= \frac{24}{5} \\\\( \frac{1}{5} )^{x}=1\\\\( \frac{1}{5} )^{x}= (\frac{1}{5})^{0}\\\\x=0[/latex]