2 cosп/6*sin(x-п/6)=-√3 решите пожалуйста.

[latex]2\cdot cos\frac{\pi}{6}\cdot sin(x-\frac{\pi}{6})=-\sqrt3\\\\2\cdot \frac{\sqrt3}{2}\cdot sin(x-\frac{\pi}{6})=-\sqrt3\\\\sin(x-\frac{\pi}{6})=-1\\\\x-\frac{\pi}{6}=-\frac{\pi}{2}+2\pi n\; ,\; n\in Z\\\\x=\frac{\pi}{6}-\frac{\pi}{2}+2\pi n\; ,\; n\in Z\\\\x=-\frac{\pi}{3}+2\pi n\; ,\; n\in Z[/latex]