2 вариант, 1 и 2 номер с подробным решением

смотри решение на фото.

а) √36 - 3√(-27) + 3√64= √6² - 3√(-3)³ + 3√4³= 6-(-3)+4= 10+3=13 б) (9/16)^-1/2 + (1 2/5)^-1= √(4²/3²) + (5/7) = 4/3 + 5/7= 1 1/3 + 5/7= 1 7/21 + 15/21= 1 22/21 = 2 1/21 в) 3√(√8-4) * 3√(√8+4)= 3√(2^3/2 - 2^2) * 3√(2^3/2 + 2^2)= (2^3/2 - 2^2)^1/3 * (2^3/2 + 2^2)^1/3= (2^3/2*2 - 2^2*2)^1/3= (2^3 - 2^4)^1/3= (8-16)^1/3= (-8)^1/3= ((-2)^3)^1/3= - 2 г) (3/4)^5/8 * (1 1/3)^1 5/8= (3/4)^5/8 * (4/3)^1 5/8= (4/3)^-5/8 * (4/3)^1 5/8= (4/3)^-5/8+ 1 5/8= (4/3)^1= 4/3= 1 1/3 д) √3 * 3√3 * 6√3= 3^1/2 * 3^1/3 * 3^1/6= 3^1/2+1/3+1/6 = 3^3/6+2/6+1/6 = 3^6/6= 3^1= 3 е) (3√(-2))^12 + 4√((-2)^8)= (-2)^12/3 + (-2)^8/4= (-2)^4 + (-2)^2= 16 + 4= 20